All circuits are identical.
Tom
All circuits are identical.
Tom
i_k(t) = sin(100·t·π + 2/3·π·k) = (e^j(100·t·π + 2/3·π·k) - e^-j(100·t·π + 2/3·π·k))/2j
i_n(t) = i_0(t) + i_1(t) + i_3(t)
The rest is trivial.
P1 is at 0 degrees, so has no "i" component, which leaves you with 1.
P2 and P3 are equal but with opposite "i" components, so they cancel and leave you with -0.5 + -0.5 = -1, as the real part is cos(120) = cos(240) = -0.5
1 + -1 = 0;
Tom
it's a lot.
Tom
Thats the one I have:
The connection between the device and the electrical network may employ a 3 meter long (max.) extension cable with a cross-section of 1.5 mm2. The use of multiple plugs or gangs is prohibited because of the danger of fire that is involved with this.
Tom